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Increasing or decreasing the shutter speed by one stop doubles or halves the amount of light reaching the sensor. How is this done in the camera? The same thing happens in aperture and I understand how that happens. i could explain it mathematically, but is that possible with shutter speed also?
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Vince "...the law of unintended consequences, sometimes, you get a truly memorable photograph" Gear: Canon G2, Canon 20D, Nikon D300...bunch of lenses http://www.flickr.com/photos/20127329@N06/ www.montalbanophotography.com |
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The total light hiting the sensor is
(1) How much (aperture) and (2) For how long (shutter speed) Another anology The total amount of water coming out of a hose is; (1) What is the diameter of the hose and (2) How long is the tap turned on?
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Flickr stream. http://www.flickr.com/photos/34094515@N00/ 500pics stream http://500px.com/Richard_Taylor |
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I understand this. What i wanted to know is: for aperture we know the f number is the ratio of the focal length and the diameter. From that i can mathematically establish that increasing or decreasing the f number by one stop, amount of light is doubled or halved. Is it possible to establish the same for shutter speed?
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Like Zona said above the numbers are fractions of a second..so expressed as fractions 30 becomes 1/30th of second, 50 is 1/50th of a second, and so on...
__________________
Vince "...the law of unintended consequences, sometimes, you get a truly memorable photograph" Gear: Canon G2, Canon 20D, Nikon D300...bunch of lenses http://www.flickr.com/photos/20127329@N06/ www.montalbanophotography.com |
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The "equivalent" of 1 F stop
Half the time = half the light. Double the time = double the light.
__________________
Flickr stream. http://www.flickr.com/photos/34094515@N00/ 500pics stream http://500px.com/Richard_Taylor |
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